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@amy do you orbit around holly because she is much more massive than you

@cam how would feel if i told you i used microsoft paint for diagrams in my master's thesis

@coriander banned

also the goblin did not accept my snacks

you are Unhelpful

hi computer scientists, what are people referring to when they say "the dragon book"

@vaporeon_ okay, for some reason std::cout << &add_rvalue_ref << "\n"; logs the number 1 to console and compilation gives me the warning "reference cannot be bound to dereferenced null pointer in well-defined C++ code; pointer may be assumed to always convert to true [-Wundefined-bool-conversion]" so um, what the fuck

@vaporeon_

#include <iostream>

int add(int a, int b) { return a + b; }

int main() {
// create type alias "AddType" for function of two ints that returns an int
// (this is just C syntax I believe)
typedef int (AddType) (int, int);

AddType&& add_rvalue_ref = (AddType&&)add;

std::cout << add_rvalue_ref(1, 2) << "\n";
}

@vaporeon_ I've actually never done it before so this'll take me a second haha

@aescling No. You would just bind the function to a reference or use a lambda, or as a last resort use a function pointer. I cannot imagine a use case for this

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