#include <iostream>
int add(int a, int b) { return a + b; }
int main() {
// create type alias "AddType" for function of two ints that returns an int
// (this is just C syntax I believe)
typedef int (AddType) (int, int);
AddType&& add_rvalue_ref = (AddType&&)add;
std::cout << add_rvalue_ref(1, 2) << "\n";
}
@vaporeon_ I've actually never done it before so this'll take me a second haha
@aescling No. You would just bind the function to a reference or use a lambda, or as a last resort use a function pointer. I cannot imagine a use case for this
@aescling yeah
@aescling lvalue
@cam it looks like bnnuy
@wallhackio @coriander Let Goblins Beam Tuesdays
@coriander i hereby permit goblins to emit beams. but only on tuesdays
@The_T "upon being reminded of having a luau at Sigourney Weaver's house, you are filled with determination"
@The_T the fuck lmao
@amy wow you've grown!! im very proud of you :)
(still short though)
@amy 🫵 smol
@amy 🫵 short
@vaporeon_ the other good Moon Cat
@cam booooooooo
@cam ........do people not do this
the clodvestigator
i answer to Caleb, Clodsire, Clodboy, Clod, Cam, and Bumby. very leftist.
videogame enjoyer. mathematics hobbyist and recovering physicist. recovering software engineer. professional wonk. prophet of The Truth. the walking embodiment of "not diagnosed, but somethings wrong". i like animals that wear cowboy hats.
number of fat cock awards received: 56
header is by @vaporeon_
"i regret ever allowing him here" ~aescling
"oh you're one of those weird movie likers" ~Ti
30+
he/him