I think a lot about how Battlefield 1's menus were written in JavaScript so they could have their web developers build a videogame UI
The actually used React to make a game UI. Why.
The PS4 doesn't allow just-in-time compilation so you don't get the performance a modern javascript engine normally guarantees so on what planet is this a good idea
@wallhackio The JavaScript Planet, a dystopian world where JavaScript is the only programming language ever invented
@vaporeon_ I love JavaScript, so delete this please
@vaporeon_ I love JavaScript, so delete this please
@wallhackio How do I deallocate memory / destroy an object in JavaScript? So that I can delete this?
@vaporeon_ npm install memory-management
@wallhackio Nooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo 
And in standard JavaScript? No NPM?
@vaporeon_ it was a joke lmao
@wallhackio But can you do any memory management in JavaScript?
const deleteThis = () => {
const temp = { _this: this };
delete temp._this;
};
@aescling @vaporeon_ this will NOT do what it's being promised to do, this is a joke
@wallhackio @aescling What will it do?
@vaporeon_ @aescling it will create an object with a single property named _this that has the value of whatever this was where the arrow function was declared
and then it will delete that property from the object
@wallhackio @aescling So creating the object initializes _this with a copy of the value of this, and only that copy gets deleted? 
@wallhackio @vaporeon_ not a copy but a refurence
@wallhackio @vaporeon_ what gets deleted is the refurence
@aescling @wallhackio Is a reference the JavaScript version of a pointer?
@vaporeon_ @wallhackio yeah basically
const o = { k: 1 };
function changeObj(o) {
o.k = 2
};
changeObj(o);
console.log(o); // { k: 2 }
@aescling @wallhackio LOL, is that because the pointer is a constant, but the contents of the object are not? In C terms, what happens here is this, right?
changeObj(struct object *o) {
o->k = 2;
}
main() {
const struct object *o = new_object(1);
changeObj(o);
printf("k: %d\n", o->k);
}
@vaporeon_ @aescling yes. in C everything is passed by value between functions, so technically the pointer is copied from main to changeObj
but pointers are just numbers so the literal address in memory that pointer refers to doesn't change
