@tindall@cybre.space back when i played with haskell i probably would have written that like

fizzbuzz :: Integer -> String
fizzbuzz x = case divisibleByMany x [3, 5] of
    [ ... ]
  where
    divisibleByMany n = filter (\y -> n `mod` y == 0)

and if i were to be really obnoxious, i’m pretty sure that lambda would be correctly expressed by ((== 0) . (mod n))